Escape Goat
Member
I'm trying to figure out this statistics problem that deals with confidence intervals.
Two large employers are considering jointly offering child care for their employees. As a part of the feasability study, they wish to estimate the mean weekly child care cost of their employees. A sample of 10 employees who use child care reveals the following amounts spent last last: 107, 92, 97, 95, 105, 101, 91, 99, 95 and 104.
Develop a 90 percent confidence interval for the population mean. Interpret the result.
Since the standard deviation isn't given I have to use the Sample divided by the square root of the population right? Gaaah! I hope someone out there knows something about stats!!
Two large employers are considering jointly offering child care for their employees. As a part of the feasability study, they wish to estimate the mean weekly child care cost of their employees. A sample of 10 employees who use child care reveals the following amounts spent last last: 107, 92, 97, 95, 105, 101, 91, 99, 95 and 104.
Develop a 90 percent confidence interval for the population mean. Interpret the result.
Since the standard deviation isn't given I have to use the Sample divided by the square root of the population right? Gaaah! I hope someone out there knows something about stats!!