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[cvxfreak]

The algebraic/graphing/whatever kind of math this is:

For the inequalities y > 4x - 3 and y < -3x + 4

a. Graph the two boundary lines and indicate with different stripes the two regions that satisfy the individual inequalities. (Did that)

b. Write the compound inequality for y. Indicate the double-hatched region on the graph hat satisfies both inequalities.

(OK, here's where I encounter some trouble. I graphed the thing correctly, that was easy. And if I'm correct, the compound inequality is 4x - 3 < y < -3x + 4. Except none of the double-hatched points satisfy the equation. WTF?! I have to be doing something wrong, or the textbook sucks ass.)

d. If x = 3, are there any corresponding y-valus in the region defined in part (b)?

(This I don't get at all. Help!)

Thanks! =/

 

[JoshuaJSlone]

The algebraic/graphing/whatever kind of math this is:

For the inequalities y > 4x - 3 and y < -3x + 4

a. Graph the two boundary lines and indicate with different stripes the two regions that satisfy the individual inequalities. (Did that)

b. Write the compound inequality for y. Indicate the double-hatched region on the graph hat satisfies both inequalities.

(OK, here's where I encounter some trouble. I graphed the thing correctly, that was easy. And if I'm correct, the compound inequality is 4x - 3 < y < -3x + 4. Except none of the double-hatched points satisfy the equation. WTF?! I have to be doing something wrong, or the textbook sucks ass.)

You must be doing a calculation wrong. If it's an (x,y) that worked for both of the individual inequalities, there's no way it's not working for the compound.

d. If x = 3, are there any corresponding y-valus in the region defined in part (b)?

(This I don't get at all. Help!)

Thanks! =/

Basically, in your graph of possible solutions to both original inequalities, does anything work for both at x=3? Or just plugging in 3 to the compound inequality...

4(3)-3 < y < -3(3) + 4
12-3 < y < -9 + 4
9 < y < -5

There's no y that's greater than 9 as well as less than or equal to -5, so there's no solution at x=3.

 

[cvxfreak]

Hmm. Thanks.

I only graphed, and didn't find a region which satisfied both individual quantities. Same problem as with the compound, basically. =/

 

[AniHawk]

Sorry, CVX, but this cracked me up:

AniHawk1: Joshua may have nailed it. Sometimes they like to trick you with a "HAHA THERES NO ANSWER" answer
CVXFREAK: I would kill the authors if they did something so retarded.
AniHawk1: Well it happens sometimes.
AniHawk1: That's EXACTLY how it's written in the book, is it?
CVXFREAK: EX-FUCKING-ZACTLY
AniHawk1: Well then I guess that's the answer.
CVXFREAK: Well, FTUTA
*This user has signed off*

:lol

 

[cvxfreak]

:lol Sorry, I was pissed off.

 

[jobber]

y= Mx + b