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[7imz]

consider the following

(i + j^2) mod m

where m is a prime number and j = 0,1,2...m

for each i we choose, m/2 numbers wouldn't appear in the result... for example

let's say we choose m = 5

i = 0... 1 4 4 1 0 <--- 2 and 3 didn't appear
i = 1... 2 1 0 2 1 <--- 3 and 4 didn't appear

i can't exactly determine the relationship... any help would be greatly appreciated.

 

[bishoptl]

pm Pimpwerx, he's got some free time.

 

[Lathentar]

I don't even get the question you're asking.

If j = 0 and i = m/2 then (m/2 + 0^2) mod m = m/2.