I figured WordPress would be difficult to scale down to what I want, but I'll take a look.
Yeah, that makes sense. Thank you for the link. I wasn't sure what these things were called.
<body>
<div class="friend" id="best_friend"><a href="https://www.google.co.uk/search?q=inbetweeners&client=opera&hs=nkc&source=lnms&sa=X&ei=TQfMU5DMDaK30QXFv4Bw&ved=0CAUQ_AUoAA&biw=1920&bih=972&dpr=1"> <img src="http://xenovive.files.wordpress.com/2011/09/tumblr_laq2f3cn5r1qzhf66o1_500.jpg"/></a></div>
<div class="friend"></div>
<div class="family"><p>family</p></div>
<div class="elves"><p>elves</p></div>
<div class="vidya"><p>vidya</p></div>
<div class="enemy"></div>
<div class="enemy" id="archnemesis"><p></p></div>
</body>div {
display: inline-block;
margin-left: 5px;
height:100px;
width:100px;
border-radius:100%;
border-width:2px;
border-style:solid;
border-color:black;
}
.friend{
border-style:dashed;
border-width:2px;
border-color:#008000;
}
.family{
border-style:dashed;
border-width:2px;
border-color:#0000ff;
}
.enemy{
border-style:dashed;
border-width:2px;
border-color:#ff0000;
}
.elves{
border-style:solid;
border-width:4px;
border-color:#008999;
}
.vidya{
border-style:dashed;
border-width:8px;
border-color:#978590;
}
#best_friend{
border-style:solid
border-width:4px;
border-color:#00c957;
}
#archnemesis{
border-style:solid
border-width:4px;
border-color:#cc0000;
}public boolean moveItem(String rfidTag, String source, String dest) throws CheckedOutException {
cursor = head;
while (cursor.getNext() != null) {
if (cursor.getInfo().getRfidTagNumber().equalsIgnoreCase(rfidTag)) {
if (cursor.getInfo().getCurrentLocation().equalsIgnoreCase(source)) {
if (cursor.getInfo().getCurrentLocation().equalsIgnoreCase("out")) {
throw new CheckedOutException();
}
try {
cursor.getInfo().setCurrentLocation(dest);
} catch (IllegalLocationException e) {
System.out.print(e.getMessage());
}
return true;
}
}
cursor = cursor.getNext();
}
if (tail.getInfo().getRfidTagNumber().equalsIgnoreCase(rfidTag)) {
if (tail.getInfo().getRfidTagNumber().equalsIgnoreCase(rfidTag)) {
if (tail.getInfo().getCurrentLocation().equalsIgnoreCase(source)) {
if (tail.getInfo().getCurrentLocation().equalsIgnoreCase("out")) {
throw new CheckedOutException();
}
try {
tail.getInfo().setCurrentLocation(dest);
} catch (IllegalLocationException e) {
System.out.print(e.getMessage());
}
return true;
}
}
}
return false;
}img { height: inherit !important; width: inherit !important; }Are you definitely setting next correctly on insert? Post the entire class.
Also, by convention, "next()" both returns the next item and moves the iterator (cursor) along. But it depends on your implementation!
public class ItemInfoNode {
private ItemInfo info;
private ItemInfoNode prev;
private ItemInfoNode next;
public ItemInfoNode(ItemInfo info, ItemInfoNode prev, ItemInfoNode next) {
this.info = info;
this.prev = prev;
this.next = next;
}
public ItemInfo getInfo() {
return info;
}
public void setInfo(ItemInfo info) {
this.info = info;
}
public ItemInfoNode getPrev() {
return prev;
}
public void setPrev(ItemInfoNode prev) {
this.prev = prev;
}
public ItemInfoNode getNext() {
return next;
}
public void setNext(ItemInfoNode next) {
this.next = next;
}
}if( cursor.getNext() == null ) {
return false;
}
// the rest of the methodOh, you're returning in the middle of the loop rather than iterating through the list (in the moveItem method). I'd check for your special case (a single item list) before you do anything else.
Also, consider checking whether or not cursor == null beforehand.
Ok GAF im sad.
A friend of mine owns a business and he hired some guy to work on an app for it. Apparently they know each other and hes gonna do his app for free.
He called me last night and told me that he wanted me, him and the guy to go out for a drink because he wanted me to meet him. I thought ok..thats weird why would I want to meet him? Well after an hour and a half of talking about all the IT stuff I do on the side because its not really my day job, the motherfucker tells me he actually works for Google!
My buddy told me that the reason why he wanted me to meet him is because the guy told him that he could put a good word of me over there if I ever wanted to apply. Because why not have a good reference AT GOOGLE!
The guy then asked me, do you code? My answer? FUCKING NO!
GAF, I probably wont ever get a Job at Google, but that shit made me sad. IT has always been my thing. I read and learn about all the new things that come out, but i cant believe that I still don't know how to code!
I see all the different languages and websites on the OP, but were do I start? which site is actually the best site thats gonna teach me to code and that I can actually use that knowledge for a career opportunity?
I'm only just starting to get my feet wet re games programming, but if you're looking for a decent introduction to game engines and the like, Unity's tutorial suite is impressive and free. I haven't dabbled with it yet, but the $20/month Unreal 4 suite with tutorials and the like looks competitive.
My answer is going to be very book-centric. Some people don't take well to reading about this sort of thing, and do better in practical situations with other people. I don't have much of value to offer there other than consider tertiary education.
Anyway, the short answer: pick a reasonably popular language that supports basic OO design (C++, Java, Python, C#, etc) and start working through some basic online tutorials. I know next to nothing about it, but don't some universities offer free online courses nowadays? I can't vouch for their value, but look into it. I've heard good things about "Dive Into Python" (available for free online).
Pick your poison, basically.
It's hard to understand early on, but the language you're using is secondary to actually thinking algorithmically or architecturally. Books like "The Mythical Man Month" and "Peopleware" are (still!) invaluable. After you've spent some time working on some projects, books like "Design Patterns" and "Refactoring" --- when read as guidelines rather than gospel --- help you think about your design.
Failing all this, find a friend and work through some problems together. It sounds obvious, even with a team of two, you'll start to butt up against some of the interesting problems working with other people ensue.
Once you have a solid understanding of a language, come back to this and follow up with some of the books mentioned here, or feel free to ask more questions. There's so many employer-specific intricacies when it comes to work environment, configuration/issue management, team process and so on that it's impossible to point to something and say "this is where you should start"*. Again, these books are useful, but the thing that makes you most attractive to employers will always be demonstrable experience. Well, that's broad. Evidence of constant, genuine critical thinking is probably the thing I'm most excited by, but if you have a good way of gauging that on a resume/interview, I'd love to hear it.
*: I can point you toward the wikipedia pages for, say, the waterfall model (which, warts and all, at least gives you a decent overview of the broad steps most project faces at one time or another) or an agile methodology, but don't get too hung up on them to start with. If you're interested, feel free to ask or have a look around yourself.
The references in the string1, string2 example are explicitly to strings. When you reassign a string, you're essentially calling the string constructor. These statements are equivalent:
String one = "1";
String two = one;
String two = "2";String one = "1";
String two = one;
String two = new String("2");(Node Reference 1) -----> (Node) -------> (String)
(Node Reference 2) -----------^int a = 1;
int b = a;
a = 2;
// a and b no longer equal
String x = "1";
String y = x;
x = "2";
// x and y no longer equal
Foo foo1 = new Foo("whatever");
Foo foo2 = foo1;
foo1 = new Foo("changed");
// foo1 and foo2 no longer equalItemNode first = new ItemNode();
first.name = "Foo";
ItemNode second = first;
first.name = "Bar";ItemNode first = new ItemNode();
first.name = "Foo";
ItemNode second = first;
first = new ItemNode(); // NEW -- reassignment of first, could easily also be 'first = someOtherNode;'
first.name = "Bar";Do this udacity course instead: https://www.udacity.com/course/cs101
, and IPv6 can only talk to v6, while v4 can only talk to v4. This usually means tunneling for right now. I can't see full adoption for another decade or so.http://www.pcmag.com/article2/0,2817,2405283,00.asp
It's not a bad summary. Basically, new numbering system, more annoying subnetting