If we take Makai at his word (and I'm still skeptical we should), it does present an interesting option.
We know there is something fishy about OceanicAir, based on johnnyquickknives's reveal. We suspect OA may be lying about having or losing his shield, because JQK switched himself with OA last night and OA's shield "vanished". At this point, we are sort of waiting on the day phase to end to see if JQK does indeed scamper off into the Tatooine sunsets with his cache of smuggled goods in tow.
If we are relatively sure enough that OA is indeed a Hutt, we may be able to kill two hutts in one night. Hopefully detain one, and have Makai shoot OA.
Let's run some scenarios shall we?
Scenario 1: Makai is telling the truth, is a Rebel without a clue a gun. OceanicAir is a Hutt. We detain someone that turns out to be a Hutt.
This is clearly a best case scenario, mind you.
We are at 18. We eliminate 2 hutts. That drops them to (worst case) 3 hutts. (4h+2I - swamped - oceanic - whoever we detain). They would now need to kill 12! of us to win. Not good for them at all.
Scenario 2a: Makai is telling the truth, is a Rebel with a gun. OceanicAir flips Rebel, we detain a Hutt.
Scenario 2b: Makai is telling the truth, is a Rebel with a gun. OceanicAir flips Hutt, we detain a Rebel.
We still come out 'ahead' in these scenarios; They're less ideal than Scenario 1, but I think more likely to occur.
Scenario 3: Makai is telling the truth, is a Rebel with a gun. OceanicAir flips Rebel. We detain a Rebel.
Obviously, this is a bad situation.
18 - 2 rebels = 16 players, Hutts could eliminate 2 in the night by taking out TWE/Zubz = 14 players. If there are 5 hutts, the game could theoretically end the next day when we detain someone.
Here's where things get ugly:
Scenario 4: Makai is lying, the filthy Hutt scum. OceanicAir is a Rebel, we detain a Rebel.
This is basically as bad as Scenario 3. Makai would almost certainly shoot OA if OA is a rebel.
Scenario 5: Makai is filthy lying Hutt scum. OceanicAir is a Hutt.
This scenario breaks down in some interesting ways:
If OceanicAir has his shield, and Makai shoots him, he would survive the shot and we would know that OceanicAir was about losing his shield. Detain imminent after that.
If OceanicAir doesn't have a shield, Makai has two options:
-5a: throw OA under the bus (thus killing a hutt)
-5b: shoot a Rebel. Doing this would basically reveal two hutts for us to detain in a row.
This is 100% worst case scenario, in terms of Rebel losses, especially if we detain a Rebel tonight.
18 players currently.
-1 Makai shoots
-1 Rebel detain
-2 hutt kills during the night (sorry TWE/Zubz, losing you both is worst case scenario)
14 players left, BUT we now have 2 all but confirmed Hutts to detain in a row.
**
Now: I think we can all agree that Makai's gun has to go tonight, one way or another (sorry Makai). If not, we can rest assured that the thief will get it (since JQK would be gone we have no switcher), and that's extra bad.
The question comes down to: we believed Makai was a Rebel enough to pull his head from the chopping block once. Do we now trust him enough with the gun to use it tonight on a single suspicious target (OA, basically)?