Wallach, it actually might be the Zmax, and not the Vamo - so many similar names. In any event it would include battery/charger/accessories.
I really need to do a better job at understanding basic electricity. I thought with the weak battery a lower resistance coil would be better. Thanks again for the feedback.
A ZMax kit with charger and batteries sounds about right for $100. With the accessories even a Vamo wouldn't be that bad, though you'd probably do better online.
What I meant about the battery is that when you lower the resistance of your attachment, the total current is going to go up pretty significantly. Smaller batteries will both get much hotter and drain much faster on lower resistance attachments for this reason. This is the reason bigger devices use "high-drain" batteries like the 18650s and such, since they're meant to handle higher current.
Just using a typical eGo example (the basic non-variable ones), they are set to put out 3.7v. This means a 1.5 resistance attachment is going to hit just over 9W of power:
3.7 (voltage) / 1.5 (resistance) = 2.46... (amperage, or current)
3.7 (voltage * 2.46... (current) = 9.126... (wattage, or power)
This is already pretty close to that upper limit for most juices before they start tasting burnt (since the juice will start vaporizing fast enough that new juice won't reach the coil in time).
This is also why variable wattage devices are so much simpler than variable voltage, since there is no thinking necessary when switching attachments that have different resistances. Since you're having the device dictate the
power, it will simply reduce or increase the voltage necessary to give you the same net on a 2.5 resistance device as it would a 1.5 resistance device, and your experience with both devices in terms of vaporization will be essentially the same. You really only need to find the "sweet spot" for your juice once and then the device will adjust itself for whatever attachment you stick on it.
Edit - For the record, to find the wattage (power) you can also simply square your voltage and then divide by your resistance. I just did it that way since it shows how to also reveal your amperage.